Solve $\displaystyle |\frac{1-(\frac{2}{3})^n}{1-\frac{2}{3}}-3|<0.01$

$\displaystyle -0.01<\frac{1-(\frac{2}{3})^n}{1-\frac{2}{3}}-3<0.01$

so $\displaystyle -0.01<\frac{1-(\frac{2}{3})^n}{1-\frac{2}{3}}-3$ and $\displaystyle \frac{1-(\frac{2}{3})^n}{1-\frac{2}{3}}-3<0.01$

simplifying: $\displaystyle -0.01<3(\frac{2}{3})^n$ and $\displaystyle 3(\frac{2}{3})^n<0.01$

I solved the right hand equation but had to reject the left hand side equation since i could not logarithm a negative number. So do i reject the whole solution or just write the right hand side equation solution?