lim x tending to infinity ((2-x)^40*(4+x)^5)/(2-x)^45

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- May 3rd 2011, 10:56 AMprasumLimits
lim x tending to infinity ((2-x)^40*(4+x)^5)/(2-x)^45

- May 3rd 2011, 11:06 AMPlato
- May 3rd 2011, 11:09 AMTheChaz
- May 4th 2011, 05:36 PMprasum
i am sorry in the numerator it is (2+x)^45

- May 4th 2011, 07:42 PMHallsofIvy
Much the same. IF you were to multiply everything out, the numerator would be x^{45} (NOT -x^45) plus terms involving lower powers of x and the denominator would be -x^{45} plus terms involving lower powers of x.

General rule: If a rational function has polynomials of the**same**degree in numerator and denominator, the limit,as x goes infinity, is the ratio of those leading coefficients. If the numerator has lower degree than the denominator, the imit, as x goes to infinity, is 0. If the numerator has higher degree than the denominator, the limit, as x goes to infinity, does not exist.