Thread: Powers and quotient of complex numbers?

2x^4+2+2\sqrt{3}i Can anyone show me how to set this up in a+bi form to solve it?

What do you mean "solve it"? There's no equation to "solve". What exactly is it you're trying to do? Can you state the original problem, word-for-word, please?

Originally Posted by homeylova223

2x^4+2+2\sqrt{3}i Can anyone show me how to set this up in a+bi form to solve it?

Solve what??

Do you mean solve 2x^4+2+2\sqrt{3}i = 0?

Then x^4 = -1 - sqrt{3}i.

Write -1 - sqrt{3}i in polar form, then x is the four fourth roots etc. How to do this has been explained to you already in several previous questions.

Thank I am sorry for my ignorance but now I understand.

Originally Posted by homeylova223

2x^4+2+2\sqrt{3}i Can anyone show me how to set this up in a+bi form to solve it?

Why are you being so darn hardheaded?
Why not learn to post in symbols? You can use LaTeX tags
We cannot help you if we cannot read the question.
You posted “2x^4+2+2\sqrt{3}I”, unreadable.
[tex] 2x^4+2+2\sqrt{3}\mathbf{i}[/tex] gives .

But that is still meaningless. WHAT is the question?
Before you post again, please learn the basics.

I am sorry I meant =0 to that equation
Sorry If I posted in a hurry.