Solve each equation. Then graph the root in the complex plane
x^5+1=0 This is what I did
x^5=-1
So that means -1+0i r= square root 1+0 so r=1 theta would be 0/1 or o
So would the polar form be 1(cos o+ i sin 0)? Did I set this problem up right?
This is the formula from my textbook I am encouraged to apply
(a+bi)^(1/p)= r^1/p cos theta+2(n)pi/p+ i sin theta+ 2(n)pi/p
I have a new question I need to clarity now that I have solved the question I asked earlier.
It involved solving this equation 3x^4+48=0 This is what I did
3x^4+48=0
3x^4=-48
x^4=-12
So in that case -12+0i I got r=12 and theta equals=pi
Then I plugged in 12^(1/4) (cos pi+2pi(0)/4) + i sin (pi+2pi(0)/4)
I end up getting 1.861 (.707+.707)
1.315+1.315i But I think my answer is wrong.
See I know cos (180/4)=.707
Look, you have to go back and review basic algebra, arithmetic etc. You have serious problems in these basic areas that are severely impacting on your ability to do questions that require these skills. The fact that you are insisting on using a calculator - incorrectly - is not helping things either. You are probably doing so in order to try and wallpaper over the problems I have mentioned - this is the worst possible reason for using a calculator.
For starters, -48 divided by 3 is NOT -12. Also, you will be expected to use exact values of the correct value of x. Furthermore, you are expected to use the exact surd value of cos(180/4 degrees) = cos(45 degrees) and sin(45 degrees) and get exact surd values for the cartesian form of the solutions (if cartesian form is required).
Sorry, but what I have said is a harsh reality - life is not going to get easier by ignoring the problem.