Solve each equation. Then graph the root in the complex plane

x^5+1=0 This is what I did

x^5=-1

So that means -1+0i r= square root 1+0 so r=1 theta would be 0/1 or o

So would the polar form be 1(cos o+ i sin 0)? Did I set this problem up right?(Wondering)

This is the formula from my textbook I am encouraged to apply

(a+bi)^(1/p)= r^1/p cos theta+2(n)pi/p+ i sin theta+ 2(n)pi/p