Can anyone show me how to simplify
2- square root 2i divided by 3+square root 6i
Now I used the conjugate 3- square root 6i
On the numerator I end up getting -6-2 square root 6- 3 square root 2i
On the denominator I end up getting 27
However I checked my answer and apparently I am wrong
What error could I have committed?
I assume that by "used" you mean you multiplied both numerator and denominator by it. Okay, (2- i sqrt(2))(3- i sqrt(6))= 2(3)- 2(i sqrt(6))- (i sqrt(2)(3)+ i^2(sqrt(2)(sqrt(6)= 6- 2i sqrt(6)- 3i sqrt(2)- sqrt(12)- not at all what you have.
(3+ i sqrt(6))(3- i sqrt(6)= 9- i^2(sqrt(6))^2= 9+ 6= 15.
Since you don't show what you did- exactly how you multiplied, it is impossible to say. I do note that 27 = 36 - 9 so you might have squared 6 instead of sqrt(6)- but then I can't see why you would have subtracted.On the numerator I end up getting -6-2 square root 6- 3 square root 2i
On the denominator I end up getting 27
However I checked my answer and apparently I am wrong
What error could I have committed?