r(\phi ) = 3/( 4+ 2sin(\phi ) for 0\leqslant \phi \leqslant 2\pi
1 .Name of the shape of the graph
2. One foci is at the origin
Find the other foci is at ( , )
The first question i think the shape of graph is Hyperpolar since a>1
The second question i do not know how to solve it please help me. Thanks
this link. (Which I got from a simple web search.) The information you need is under the sections "Focus" and "Polar Form Relative to Center."
If you really don't have access to these formulas you should read most of this article.