Thread: Polar form of a linear equation?

Write the equation in rectangular form

r= 5 sec (theta- 60 degrees)

How would I do this usually I am used to r being on the "other side" of the equation.

Originally Posted by homeylova223

Write the equation in rectangular form

r= 5 sec (theta- 60 degrees)

How would I do this usually I am used to r being on the "other side" of the equation.

Rearrange this as r*cos(theta - 60) = 5

Now expand the cos(theta - 60) and that will give you two terms that involve x = r*cos(theta) and r*sin(theta).

-Dan