$\displaystyle \displaystyle y=e^{-3x} - e^{2x}$

I factored it to: $\displaystyle \displaystyle y=(e^{-3x})(e^{2x}-1)$

$\displaystyle \displaystyle e^{-3x}$ Never equals zero (right?)

How would I solve for $\displaystyle \displaystyle e^{2x}-1=0$?

Edit: I know the answer is $\displaystyle x=0$ by looking at it, but how would I solve a similar equation?