# Math Help - Conics: Hyberbolas

1. ## Conics: Hyberbolas

The question is asking to find the standard form of the equation of the hyperbola with the given characteristics:

Verticies: (-2,1), (2,1)
Foci: (-3,1), (3,1)

using the c^2=A^2 + B^2
I find that a = 2(verticies) and c = 3(foci)
so b= √5

Plugging everything back in the standard equation I got

((x^2)/4) - (((y-1)^2)/25) = 1

2. $\frac{x^2}{4} - \frac{(y - 1)^2}{25} = 1$

looks good to me!

3. Originally Posted by NeoSonata
The question is asking to find the standard form of the equation of the hyperbola with the given characteristics:

Verticies: (-2,1), (2,1)
Foci: (-3,1), (3,1)

using the c^2=A^2 + B^2
I find that a = 2(verticies) and c = 3(foci)
so b= √5 <--- b² = 5
Compare with your equation of the hyperbola!

Plugging everything back in the standard equation I got

((x^2)/4) - (((y-1)^2)/25) = 1 <--- unfortunately wrong. See above.