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Math Help - Conics: Hyberbolas

  1. #1
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    Conics: Hyberbolas

    The question is asking to find the standard form of the equation of the hyperbola with the given characteristics:

    Verticies: (-2,1), (2,1)
    Foci: (-3,1), (3,1)


    using the c^2=A^2 + B^2
    I find that a = 2(verticies) and c = 3(foci)
    so b= √5


    Plugging everything back in the standard equation I got

    ((x^2)/4) - (((y-1)^2)/25) = 1

    Can someone please confirm that my answer is correct. Thanks!
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  2. #2
    Super Member TheChaz's Avatar
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    \frac{x^2}{4} - \frac{(y - 1)^2}{25} = 1

    looks good to me!
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  3. #3
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    Quote Originally Posted by NeoSonata View Post
    The question is asking to find the standard form of the equation of the hyperbola with the given characteristics:

    Verticies: (-2,1), (2,1)
    Foci: (-3,1), (3,1)


    using the c^2=A^2 + B^2
    I find that a = 2(verticies) and c = 3(foci)
    so b= √5 <--- bē = 5
    Compare with your equation of the hyperbola!



    Plugging everything back in the standard equation I got

    ((x^2)/4) - (((y-1)^2)/25) = 1 <--- unfortunately wrong. See above.

    Can someone please confirm that my answer is correct. Thanks!
    ...
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