# Conics: Hyberbolas

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• Apr 7th 2011, 06:18 PM
NeoSonata
Conics: Hyberbolas
The question is asking to find the standard form of the equation of the hyperbola with the given characteristics:

Verticies: (-2,1), (2,1)
Foci: (-3,1), (3,1)

using the c^2=A^2 + B^2
I find that a = 2(verticies) and c = 3(foci)
so b= √5

Plugging everything back in the standard equation I got

((x^2)/4) - (((y-1)^2)/25) = 1

Can someone please confirm that my answer is correct. Thanks!
• Apr 7th 2011, 06:24 PM
TheChaz
$\frac{x^2}{4} - \frac{(y - 1)^2}{25} = 1$

looks good to me!
• Apr 8th 2011, 10:03 AM
earboth
Quote:

Originally Posted by NeoSonata
The question is asking to find the standard form of the equation of the hyperbola with the given characteristics:

Verticies: (-2,1), (2,1)
Foci: (-3,1), (3,1)

using the c^2=A^2 + B^2
I find that a = 2(verticies) and c = 3(foci)
so b= √5 <--- bē = 5
Compare with your equation of the hyperbola!

Plugging everything back in the standard equation I got

((x^2)/4) - (((y-1)^2)/25) = 1 <--- unfortunately wrong. See above.

Can someone please confirm that my answer is correct. Thanks!

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