• Apr 6th 2011, 08:33 PM
NeoSonata
Find standard form of the equation of ellipse with given characteristics.

Vertices: (0,2), (8,2)
minor axis of length 2

With that information I found the center: (4,2)

minor axis of length 2 means I would use 2b=2?
So b=1

I am lost after this that.
• Apr 6th 2011, 08:53 PM
pickslides
Your equation is $\displaystyle \frac{(x-h)^2}{a^2}+\frac{(x-k)^2}{b^2}=1$

You are given the length of the minor axes to be 2 therefore you have the points (0,2),(8,2),(4,0),(4,4) and centre (4,2), major axis is 4.

You have lots of information here, firstly can you find (h,k)?
• Apr 6th 2011, 09:06 PM
NeoSonata
(h,k) is the center which is (4,2)

Can you please explain where you got the points (4,0), (4,4) and how you found the major axis to be 4?

Is it because the distance between the center and one of the vertices is 4 ?
• Apr 6th 2011, 09:11 PM
pickslides
Good work with finding (h,k)

Quote:

Originally Posted by NeoSonata
(h,k) is the center which is (4,2)

Can you please explain where you got the points (4,0), (4,4)

You told me the minor axes was 2.

Quote:

Originally Posted by NeoSonata
and how you found the major axis to be 4?

Is it because the distance between the center and one of the vertices is 4 ?

Yep.