Results 1 to 2 of 2

Math Help - Increasing function

  1. #1
    Junior Member Hardwork's Avatar
    Joined
    Sep 2010
    Posts
    36

    Increasing function

    Ok, I've a question. For a certain function f(x), it's been shown:

    If x > 2^k then f(x) > f(2^k) > \frac{1}{2}k.

    Fine. My question is the following: how does it follow that:

    f(x) \to +\infty when x \to +\infty.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Grand Panjandrum
    Joined
    Nov 2005
    From
    someplace
    Posts
    14,972
    Thanks
    4
    Quote Originally Posted by Hardwork View Post
    Ok, I've a question. For a certain function f(x), it's been shown:

    If x > 2^k then f(x) > f(2^k) > \frac{1}{2}k.

    Fine. My question is the following: how does it follow that:

    f(x) \to +\infty when x \to +\infty.
    For any real r>0,\ f(x)>r for all x>2^{2r}.

    That is $$f(x) is bigger than any given real for $$x sufficiently large

    CB
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. How to tell where this function is increasing?
    Posted in the Calculus Forum
    Replies: 7
    Last Post: January 4th 2010, 04:27 PM
  2. increasing function
    Posted in the Calculus Forum
    Replies: 4
    Last Post: November 21st 2009, 07:12 AM
  3. increasing function
    Posted in the Differential Geometry Forum
    Replies: 8
    Last Post: August 11th 2009, 08:04 PM
  4. Increasing Function
    Posted in the Pre-Calculus Forum
    Replies: 1
    Last Post: May 21st 2009, 01:47 PM
  5. Increasing function
    Posted in the Calculus Forum
    Replies: 2
    Last Post: July 1st 2008, 11:50 PM

Search Tags


/mathhelpforum @mathhelpforum