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- April 5th 2011, 05:10 AMjacsLimit with cubic factor
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- April 5th 2011, 05:15 AMjacsLimit with cubic factor
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I suspect somehow i need to utlise

although i am not sure how to do it

thanks - April 5th 2011, 05:19 AMFernandoRevilla
Now, .

- April 5th 2011, 05:28 AMamul28

which is one of generalised form

- April 5th 2011, 05:43 AMTheChaz
As has been noted above, this is the "alternate" definition of the derivative (or "derivative at a point")..

If f(t) = t^(1/3)

f'(t) is the above limit, with t in place of 2.

So the above limit is f'(2) = (1/3)*2^(1/3-1)

OR.

View the numerator as one factor in the difference of cubes, and multiply by ...(something I'd rather not type) to "rationalize".

Then you can use direct substitution. - April 5th 2011, 07:03 AMTheEmptySet