The human cannonball is shot out of a cannon with an initial velocity of 70 mph 10 feet above the ground at an angle of 35 degrees.

What is the maximum range of the cannon?

I did this parametric equation

x=t v cos

y= t v sin-1/2gt^2+h

So I set y to zero and to find t and I got t= 3.14

Then I plug it in back to t in and got x=180.04

As I checked the answer so I am not sure what I may have done wrong?

These are the formulas I used

x=t 70 cos (35)

y= t 70 sin (35)-16t^2+10