The human cannonball is shot out of a cannon with an initial velocity of 70 mph 10 feet above the ground at an angle of 35 degrees.
What is the maximum range of the cannon?
I did this parametric equation
x=t v cos
y= t v sin-1/2gt^2+h
So I set y to zero and to find t and I got t= 3.14
Then I plug it in back to t in and got x=180.04
As I checked the answer so I am not sure what I may have done wrong?
These are the formulas I used
x=t 70 cos (35)
y= t 70 sin (35)-16t^2+10