Show that tan x is an odd function: tan (-x) = - tan x? Not sure how to do this, help would be much appreciated
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Of course is $\displaystyle \tan x = \frac{\sin x}{\cos x}$ ... $\displaystyle \sin x$ is an odd function and $\displaystyle \cos x$ an even function... what about the ratio?... Kind regards $\displaystyle \chi$ $\displaystyle \sigma$
Originally Posted by brumby_3 Show that tan x is an odd function: tan (-x) = - tan x? Not sure how to do this, help would be much appreciated What definition of tan are you working with? CB
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