Hello everybody,

I'm having trouble with this problem.

$\displaystyle 3*2^x^-^2 = 6-2^x^-^2$

This homework question has me completely stumped, my teacher said that we should first solve for $\displaystyle 2^x^-^2$ then take the log, but I have no clue what she means, and there is no similar problems in the book. I wish I would've asking her to clarify this. can anyone help me?

Thank You