Find c so that these vectors are mutually perpendicular: a = <c,−2, 3> and b = <c, c,−5>. how would you go about doing this. I know how to apply the cross product.
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Two vectors are perpendicular if their dot product is $\displaystyle \displaystyle 0$.
thanks for response and yes i agree if its 0 its mutually perpendicular. would i have to put a = <c,−2, 3> and b = <c, c,−5> into its determinant form then solve?
No, take the dot product and set it equal to $\displaystyle \displaystyle 0$. Then solve the resulting quadratic.
ok i see i got an answer of −3 or it could be 5 i think that's correct
Yes that is correct.
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