1) x=(x^3)-(3x^2)-13x+15
Its zeros are ?,?,? (3 answers)
2)The polynomial of degree 4, p(x) has a root of multiplicity 2 at x=2 and roots of multiplicity 1 at x=0 and x=-2. Its lead coefficient is 5.
Find a formula for . p(x)
did you mean $\displaystyle f(x) = x^3 - 3x^2 - 13x + 15$ ? if so, note that $\displaystyle f(1) = 0$ ... you should now be able to find the other two zeros.
look at the following polynomial in factored form ...
$\displaystyle p(x) = ax(x-b)(x-c)^2$
it has a leading coefficient $\displaystyle a$ , root at $\displaystyle x = 0$ , root at $\displaystyle x = b$ , and a root of multiplicity two at $\displaystyle x = c$