# Finding Equation for Axis of Symmetry?

If I've understood the dreadful wording, then, for a parabola of the form $y=ax^2+bx+c$, the the axis of symmetry will be where $x=\frac{-b}{2a}$
If you don't want to do that, then just find the x ordinate of the point which is halfway between $(-3,3)$ and $(5,3)$, as the axis of symmetry will bisect the parabola directly, and so you will find an equation of the form $x=[number]$