I'm stuck on this question; Suppose c is a number such that area(1/x,1,c)> 1000. Explain why c> 2^1000 can someone clarify what natural log is for me? thank you so much (:
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Originally Posted by dondonlouie I'm stuck on this question; Suppose c is a number such that area(1/x,1,c)> 1000. Explain why c> 2^1000 I assume by ‘area’ you mean $\displaystyle \int_1^c {\frac{{dx}}{x}} = \ln (c)$. So you want to solve $\displaystyle \ln(c)>10^3$. Recall that $\displaystyle e^{\ln(c)}=c.$
Originally Posted by Plato I assume by ‘area’ you mean $\displaystyle \int_1^c {\frac{{dx}}{x}} = \ln (c)$. So you want to solve $\displaystyle \ln(c)>10^3$. Recall that $\displaystyle e^{\ln(c)}=c.$ wouldn't it just be 1000?
Originally Posted by dondonlouie wouldn't it just be 1000? No indeed! If $\displaystyle \ln(c)>1000$ then $\displaystyle c>e^{1000}.$
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