the above line bisects the obtuse angle ... the bisector of the acute angle will be perpendicular to the above line.
Find the equation of the lines that bisect the acute and obtuse angles formed by the lines with the given equations.
y=2/3x+1
y=-3x-2
Know I used the formula d= Ax+By+C/square root A^2+B^2
To get square root for these functions
So I got (2/3x-1y+1)/(-1.20) and (-3x-1y-2)/(3.162)
Then when I cross multiply these my answer come up wrong. Can anyone please help me?