The question:
$\displaystyle |\sqrt{w^2 - 4} + w| = 2$ such that w is a complex number
I tried using the identity $\displaystyle |z|^2 = z\overline{z}$ to get a solution, but it appears to create a mess. :/
Any assistance would be great.
The question:
$\displaystyle |\sqrt{w^2 - 4} + w| = 2$ such that w is a complex number
I tried using the identity $\displaystyle |z|^2 = z\overline{z}$ to get a solution, but it appears to create a mess. :/
Any assistance would be great.
OK, so I've worked out what you've done so far. This is what I've done:
Let z = x + iy
$\displaystyle (x + iy + x - iy)^2 - 2$
$\displaystyle (2x)^2 - 2$
$\displaystyle 4x^2 - 2$
So unless I'm mistaken, this is a parabola. I'm fairly sure this isn't the correct solution. :/