For which values of the constant d does the function x^2+(d-1)x+d have only one solution? State an exact answer. Thank you in advance!
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Originally Posted by Anna55 For which values of the constant d does the function x^2+(d-1)x+d have only one solution? State an exact answer. Thank you in advance! What value(s) of $\displaystyle d$ make the discriminant zero. You know: $\displaystyle b^2-4ac=0$
I do not understand. Don't I need to know the value of a and c to make the discriminant equal zero?
$\displaystyle b^2-4ac$ refers to the notation used in the standard quadratic form which is $\displaystyle ax^2+bx+c=0$ For you $\displaystyle a = 1$ and $\displaystyle b= d-1$ and $\displaystyle c = d$
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