Find an area of a parallelogram determined by the points P(7,-5,5), Q(-5,10,10), R(-8,8,-4) and S(-20,23,1).
PQ = -12i + 15j + 5k
RS = -12i + 15j + 5k
PS = -27i + 28j - 4k
RQ = 3i -2j -14k
* This is what I have, I am lost at the moment. I have PQ and RS are parallel. I know I need to use the cross product. Any assistance on what to do next????