Find an area of a parallelogram determined by the points P(7,-5,5), Q(-5,10,10), R(-8,8,-4) and S(-20,23,1).

-->

PQ = -12i+ 15j+ 5k-->

RS = -12i+ 15j+ 5k>

--

PS = -27i+ 28j- 4k-->

RQ = 3i-2j-14k

* This is what I have, I am lost at the moment. I have PQ and RS are parallel. I know I need to use the cross product. Any assistance on what to do next????