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Math Help - finding the equation of the circle

  1. #1
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    finding the equation of the circle

    find the equation of the circle that passes through the (2,2) and tangent to the line x =1 and x = 6?


    What would be the best way to answer this question? can you please give me an illustration?


    thank you in advance and God bless you..

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  2. #2
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    The equation of a circle is \displaystyle (x-h)^2+(y-k)^2= r^2 you have the point (2,2) to sub in and given it is tangent to x=1 and x=6 then the radius is half the difference of these two numbers.
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  3. #3
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    An obvious point- since x= 1 and x= 6 are parallel, the center of the circle lies on the vertical line half way between them. That immediately gives you both the x-coordinate of the center and the radius. Then use pickslides equation, with x= y=2, to find the y-coordinate of the center.
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