# Lines

• Aug 2nd 2007, 11:09 PM
charrie berri
Lines
Sorry to bother you guys >__<

Find the following distances between the parallel lines

3x+2y=12 and 3x+12y= -14

The horizontal distance

THe vertical distance

The shortest distance

I dunno how to find these distances

OMG THANKS A MILLION! T___T I would've never survived w/o your help
• Aug 2nd 2007, 11:21 PM
tukeywilliams
those are not parallel lines.
• Aug 2nd 2007, 11:29 PM
charrie berri
Oops i meant 3x+2y= -14

FIXED
• Aug 2nd 2007, 11:43 PM
tukeywilliams
Use the formula from the other post to compute the shortest distance (i.e perpendicular distance) or $\displaystyle d = \frac{|Am + Bn + C|}{\sqrt{A^2+B^2}}$. To find the vertical distance, choose a point on each line that has the same x-coordinate (then use the formula $\displaystyle d = |y_2-y_1|$). Likewise, for the horizontal distance, choose a point on each line that has the same y-coordinate (then use the formula $\displaystyle d = |x_2-x_1|)$. Really, $\displaystyle x = 0, \ y = 0$ are the easiest choices.