f(x)=ln(2-5x)

I know the domain is x less than 2/5 but what on earth is the range? I don't know if I'm having some sort of mental block or what.

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- Mar 13th 2011, 09:25 PMtheridonRange of a relatively simple function
f(x)=ln(2-5x)

I know the domain is x less than 2/5 but what on earth is the range? I don't know if I'm having some sort of mental block or what. - Mar 13th 2011, 09:38 PMmr fantastic
- Mar 13th 2011, 09:42 PMtheridon
For some reason when I graph it on my ti83, it goes down only to a certain point-about y=-1.21109

This is what is throwing me off. Is my calculator at fault? - Mar 14th 2011, 06:28 AMHallsofIvy
Probably what is happening is that your calculator doesn't want to show the vertical asymptote at x= 2/5. The graph very rapidly approaches that vertical line.

- Mar 14th 2011, 06:46 AMskeeter
free graphing program with better resolution than a TI ...

Graph