Hi Relation and gives How do I solve above?
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Originally Posted by pelle2004 Hi Relation and gives How do I solve above? When dealing with real numbers, this logic might be handy:
Originally Posted by pelle2004 Hi Relation and gives How do I solve above? Square both sides to get a quadratic. Solve the quadratic and check the solutions by substituting back into the above to make sure you have not introduced spurious solutions by squaring. CB
Not shure what I should do by 'quadratic' I guess.... But then I need some help to be able to solve x for y=0 ...
Originally Posted by pelle2004 Not shure what I should do by 'quadratic' The last quoted line is OK. A quadratic equation has the solution you know: a = 305.25, b = 23500, c = -250000 so you can calculate the value of x. (Btw the negative solution isn't very plausible with your question)
Originally Posted by pelle2004 Less confusion if next is rearranging this way: 35SQRT(x^2 + 80x) = 2x + 1000 ; then: 1225x^2 + 98000x = 4x^2 + 4000x + 1000000 1221x^2 + 94000x - 1000000 = 0
Originally Posted by earboth The last quoted line is OK. A quadratic equation has the solution you know: a = 305.25, b = 23500, c = -250000 so you can calculate the value of x. (Btw the negative solution isn't very plausible with your question) x=9.4727287939 /Thanks!!
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