How would I find the horizontal asymptote of this function?
This is ugly, but might be the best way....
(Considering "the bottom" to be "1")
Multiply top and bottom by the conjugate ...
Then you'll have 3x on top. As , the bottom will become closer to just
So we're looking at 3x over 2x --> 3/2.
Yeah... I'm betting soroban can do it more elegantly!
Hello, youngb11!
Thanks for the compliment, Chaz!
This is definitely not elegant, but it is more algebraically complete.
We want: . .if it exists.
As TheChaz suggested, multiply top and bottom by the conjugate:
. .
. .
Divide top and bottom by
. .
. .
. . . . . . . . . .