Results 1 to 3 of 3

Math Help - Bhaskara equation help

  1. #1
    Newbie
    Joined
    Feb 2011
    Posts
    8

    Bhaskara equation help

    Hello, I'm having problems to solve this equation:

    6x^2-5x^-^1+1=0

    I really don't know how to do.

    I don't know if it will be 5.\frac{1}{x} or \frac{1}{5x} and how do I get a b and c to make the use bhaskara formula.

    The answer is {2, 3}

    Thanks in advance
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Super Member
    earboth's Avatar
    Joined
    Jan 2006
    From
    Germany
    Posts
    5,829
    Thanks
    123
    Quote Originally Posted by lucas7 View Post
    Hello, I'm having problems to solve this equation:

    6x^2-5x^-^1+1=0

    I really don't know how to do.

    I don't know if it will be 5.\frac{1}{x} or \frac{1}{5x} and how do I get a b and c to make the use bhaskara formula.

    The answer is {2, 3}

    Thanks in advance
    1. As far as I'm informed Bhaskara's formula is used to solve quadratic equations. After some transformations your equation will be a cube equation:

    6x^2-5 \cdot \dfrac1x + 1=0~\implies~6x^3+x-5=0

    If you don't want to use numerical methods you have to use Cardano's formula.

    2. If and only if the original equation is

    6x-5 \cdot \dfrac1x +1=0~\implies~6x^2+x-5=0

    Then you can use Bhaskara's formula.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Feb 2011
    Posts
    8
    Hey, thanks for the answer.

    Well I got to the \frac{6x^3-5+x=0}{x} point. But I do not understand how to reduce it to x^2 so I can use the bhaskara forum and solve it myself. Could you or someone please explain it? Thanks so much in advances
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 1
    Last Post: April 11th 2011, 01:17 AM
  2. Partial differential equation-wave equation - dimensional analysis
    Posted in the Differential Equations Forum
    Replies: 3
    Last Post: August 28th 2009, 11:39 AM
  3. Replies: 2
    Last Post: May 18th 2009, 12:51 PM
  4. Replies: 2
    Last Post: April 28th 2009, 06:42 AM
  5. Replies: 1
    Last Post: October 23rd 2008, 03:39 AM

Search Tags


/mathhelpforum @mathhelpforum