Hello, I'm having problems to solve this equation:

$\displaystyle 6x^2-5x^-^1+1=0$

I really don't know how to do.

I don't know if it will be $\displaystyle 5.\frac{1}{x}$ or $\displaystyle \frac{1}{5x}$ and how do I get a b and c to make the use bhaskara formula.

The answer is {2, 3}

Thanks in advance