# Thread: Rearranging an equation and finding the x and y intercepts

1. ## Rearranging an equation and finding the x and y intercepts

For a line, the x-intercept is (4,0) and the y-intercept is (0,3) with the equation of the line in standard form as y= -(3/4)x + b
a) Rearrange the equation of the line in standard form into the form (x/c)+(y/d)=1 for suitable non-zero numbers c and d.
b) An equation in the form (x/c)+(y/d)=1 describes a line in the plane. What are its x-intercept and it's y-intercept?

2. You know the $\displaystyle y$ intercept, so you know the value of $\displaystyle b$...

3. Originally Posted by brumby_3
For a line, the x-intercept is (4,0) and the y-intercept is (0,3) with the equation of the line in standard form as y= -(3/4)x + b
When x=0, what is y?

a) Rearrange the equation of the line in standard form into the form (x/c)+(y/d)=1 for suitable non-zero numbers c and d.
Whatever you got for b in the first equation, divide the entire equation by it.

b) An equation in the form (x/c)+(y/d)=1 describes a line in the plane. What are its x-intercept and it's y-intercept?
When y= 0, what is x? When x= 0, what is y?