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Math Help - Rearranging an equation and finding the x and y intercepts

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    Smile Rearranging an equation and finding the x and y intercepts

    For a line, the x-intercept is (4,0) and the y-intercept is (0,3) with the equation of the line in standard form as y= -(3/4)x + b
    a) Rearrange the equation of the line in standard form into the form (x/c)+(y/d)=1 for suitable non-zero numbers c and d.
    b) An equation in the form (x/c)+(y/d)=1 describes a line in the plane. What are its x-intercept and it's y-intercept?
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    You know the \displaystyle y intercept, so you know the value of \displaystyle b...
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    Quote Originally Posted by brumby_3 View Post
    For a line, the x-intercept is (4,0) and the y-intercept is (0,3) with the equation of the line in standard form as y= -(3/4)x + b
    When x=0, what is y?

    a) Rearrange the equation of the line in standard form into the form (x/c)+(y/d)=1 for suitable non-zero numbers c and d.
    Whatever you got for b in the first equation, divide the entire equation by it.

    b) An equation in the form (x/c)+(y/d)=1 describes a line in the plane. What are its x-intercept and it's y-intercept?
    When y= 0, what is x? When x= 0, what is y?
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