1. ## vectors

if this is wrong place please mvoe i dont know what topic vector belong in

so basically this i sthe qu

find x so the two vectors are perpendiculs

v1= (1,1,0)^T
v2= (x,1-1,)^T

the nfind a cross product

i dont have any source materials/TEXTS before people say read your text book etc which always happen. i am not in school...

2. Two vectors are perpendicular if there dot product is zero.
$\cdot=ap+bq+cr$

3. Originally Posted by mathcore
if this is wrong place please mvoe i dont know what topic vector belong in

so basically this i sthe qu

find x so the two vectors are perpendiculs

v1= (1,1,0)^T
v2= (x,1-1,)^T

the nfind a cross product

i dont have any source materials/TEXTS before people say read your text book etc which always happen. i am not in school...
You have no access to a library so that you could borrow an appropriate textbook?

Furthermore, here is what I get when I use Google and the search string 'two vectors perpendicular': Google

I'm sure with a little browsing many useful websites would be found ....

The same thing can be done with 'cross product'.

People don't mind helping, but most would prefer that the obvious possibilities for help, some of which admittedly require a little effort, have first been exhausted by the person askng for help.

4. Originally Posted by Plato
Two vectors are perpendicular if there dot product is zero.
$\cdot=ap+bq+cr$

i didnt say i dont know what makes t wo vector perpemdiculuar

i said i dont know HOW to make them

so what we have here is a power ^T on each side what do u do with this

and fantastic guy the google link dont help. yes i have looked on all those websites and i dont get it thats why im askin help.

5. Originally Posted by mathcore
i didnt say i dont know what makes t wo vector perpemdiculuar
i said i dont know HOW to make them
so what we have here is a power ^T on each side what do u do with this
.
Can you solve $(1)(x)+(1)(1)+(0)(-1)=0~?$
The ^T is for transpose: $\[
\left\langle {a,b,c} \right\rangle ^T = \left[ {\begin{array}{*{20}c} a \\ b \\ c \\ \end{array} } \right]$

Originally Posted by mathcore
and fantastic guy the google link dont help. yes i have looked on all those websites and i dont get it thats why im askin help.
Now for your attitude. It is not our fault that you seem to not be able to make yourself clear as to what you really need to ask. Moreover, you choose to use sort of web-blather, no caps, no complete sentences, etc. All of that makes it difficult to read your posts.

6. Originally Posted by mathcore
i didnt say i dont know what makes t wo vector perpemdiculuar

i said i dont know HOW to make them

so what we have here is a power ^T on each side what do u do with this

and fantastic guy the google link dont help. yes i have looked on all those websites and i dont get it thats why im askin help.
The ^T is merely notation to represent the vectors as column matrices. Wherever the question has come from assumes that you are familiar with this notation.

For all practical purposes the vectors are <1,1,0> and <x,1,-1>. You've been given the tool for solving the question. And if none of the Google links help I'd be greatly surprised.

Where has the question come from and why are you trying to solve it?

7. so does it means x + 1 + -1 = o so x = 0

8. Originally Posted by mathcore
so does it means x + 1 + -1 = o so x = 0
Is you real problem that you cannot do basic algebra?
$(1)(x)+(1)(1)+(0)(-1)=x+1=0$ that means $x=-1$.

9. ok thanks

Using the cross product, find a unit vector ^c
so that ^a;^b and ^c are the unit vectors for a right-handed coordinate system.

i have the unit vectors ^a and ^b but what do i need to do next? is it asking me find cross product a and b? or ^a and ^b?

sorry but why is this is PRE university? this is university materiall...

10. Originally Posted by mathcore
ok thanks