The slope of line AB is thus the altitude from C to AB is .
The slope of line AC is thus the altitude from B to AC is .
Find the intersection.
What form are those equations in? So far I've only learned standard, point-slope, and slope intercept. It seems like you combined slope-intercept and point slope... I know to find the intersection of two equations you have to simplify then use systems, and I tried playing around with your equations, but I got a fraction....
Could you help more?
I think you misunderstood my question... I know how you came up with the equations (and now I know what form they are in) and I understand that by finding two intersection points, you find all three.
What I'm having a problem with is solving them--here's what I tried:
y= 4 (x-3) + 1
y= 4x - 13 + 1
y= 4x - 11
y= -8/3(x-7)-5
y= -8/3x + 56/3 -5 multiply everything by three (to get rid of the fraction)
3y= -8x + 56 - 15
3y = -8x + 41
And then I would use systems (for 3y = -8x + 41 and y= 4x - 11) to solve for x and y. But I get fractions/decimals..