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Math Help - Vectors problem.

  1. #1
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    Vectors problem.

    ABCD is a parallelogram, where A is (4,2), B is (-6,1) and D is (-3,-4). Find the coordinates of C.

    My attempt:
    \vec{AC} = \vec{BD}
    First I'll find the vector \vec{BD} then solve for its magnitude:
    \bec{BD} = \vec{OD} - \vec{OB} => (-3-(-6),(-4-1) => (3,-5)
    Now I'll find the magnitude:
    \vec{BD} = \sqrt{(3)^{2}+(-5)^{2}}
    \vec {BD} = \sqrt{34}
    Unfortunately, this is the farthest I can get. I tried isolating for \vec{C} but didn't work out as I only got 1 value and not two. I don't have the slightest clue on how to solve this problem (never saw it in my work or problems) and it threw me off completely. Thanks in advance.
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  2. #2
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    Quote Originally Posted by Pupil View Post
    ABCD is a parallelogram, where A is (4,2), B is (-6,1) and D is (-3,-4). Find the coordinates of C.
    let the coordinates of C be (x,y)

    \vec{AB} = \vec{DC}

    <-10,-1> = <x-(-3), y-(-4)><br />

    C = (-13,-5)
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