Divide the second equation by the first to give .
Now substitute this into the third equation and you can solve for , and then use that to solve for .
Please solve this equation system:
xy+x+y=11
xz+x+z=14
yz+y+z=19
First I factorized everything:
(x+1)(y+1)=12
(x+1)(z+1)=15
(y+1)(z+1)=20
After that I tried the substitution method, however I fail to solve it.
I should I countinue?
Thank you in advance!