Check the first step.
It should be
It becomes
Now proceed.
Use an algebraic strategy to verify that the point given for the function is either a maximum or minimum.
f(x) = x3 - 3x; (-1,2)
The answer should be 0 yet i get another answer. This is what i did:[COLOR=rgb(0, 0, 0)]
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"h's" cancel
It should = 0 however and the slopes should be negative right side and positive left side I believe proving it is a maximum.
Yeh that's what I did. I'm new with latex so I really ment h dividing that whole part not just "a" which gives me the answer that I got
Alright so I tried again hopefully correctly but in the end I still didn't get that 0 i'm looking for
[tex](-1+h)^3-3(-1+h)-[(-1)^3-3(-1)]/h[\MATH]
[tex]-1+3h-3h+3h^3-[-1+3][\MATH]
[tex]-1+1-3+3h-3h+3h^3/h[\MATH]
"h's cancel plus other numbers"
[tex]3h-3[\MATH]
[tex]3(0.01)-3 = -2.97[\MATH]
[tex]3(-0.01)-3 = -3.03[\MATH]
[tex]-2.97+(-3.03)/2 = -3[\MATH]
This time i get -3 instead of 0 and both "h's" left and right sides are negative instead of being left positive and right negative proving it to be a maximum
Alright after many many tries i managed to get a tangent of 0.0001. Not 0 but really really close so I guess that's good enough and I also got the right side to be negative and left side positive proving its a maximum. The problem was that I made a simple but at the same time major mistake simplifying.