Hi, I have the following exercise...

By completing the square in $\displaystyle x$ and $\displaystyle y$, and so by eliminating the linear terms, put the conic

$\displaystyle 9x^2+4y^2-36x-24y+36=0$

into standard form

___

Well, I have completed the square, but how do I get the standard form of this conic?? :-/

$\displaystyle (3x-6)^2+(2y-6)^2=36$