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Math Help - Solving equations in cartesian form.

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    Solving equations in cartesian form.

    Solve the following in cartesian form:
    z^4=16
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    \displaystyle z^4 = 16

    \displaystyle z^4 - 16 = 0

    \displaystyle (z^2)^2 - 4^2 = 0

    \displaystyle (z^2 - 4)(z^2 + 4) = 0

    \displaystyle z^2 - 4 = 0 or \displaystyle z^2 + 4 = 0

    \displaystyle z^2 = 4 or \displaystyle z^2 = -4

    \displaystyle z = \pm 2 or \displaystyle z = \pm 2i.


    So the solutions are \displaystyle z = -2, z = 2, z = -2i, z = 2i.
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    Quote Originally Posted by johnsy123 View Post
    Solve the following in cartesian form:
    z^4=16
    Solve z^4 - 16 = 0 (I suggest that factorising is a good approach to take).

    If you need more help, please post all your work and say where you get stuck.

    And if solutions over the complex number field are required, you should have said so.
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