Thread: Prove (asin t - bcos t) ^2 (b sint t + a cost t)^2 = a^2 + b^2

(asin t - bcos t) ^2 (b sint t + a cost t)^2 = a^2 + b^2

I tried, believe me.
Its too difficult.

Originally Posted by ilyhyunbin

(asin t - bcos t)^2 + (b sint t + a cost t)^2 = a^2 + b^2

I tried, believe me.
Its too difficult.

The red plus sign I added is not unimportant. Now expand and simplify using the Pythagorean Identity.

Maybe it's just because I'm up too late. What the heck are "b sint t" and "a cost t?"

-Dan

Originally Posted by topsquark

Maybe it's just because I'm up too late. What the heck are "b sint t" and "a cost t?"

-Dan

I believe that a and b are constants that are multiplying the sin(t) and cos(t) functions.

Well, the OP doesn't seem to have a problem with it (or hasn't come back yet.) My problem is that extra "t" in "sint t" and "cost t". Sorry for not being more clear.

-Dan