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Math Help - Prove (asin t - bcos t) ^2 (b sint t + a cost t)^2 = a^2 + b^2

  1. #1
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    Exclamation Prove (asin t - bcos t) ^2 (b sint t + a cost t)^2 = a^2 + b^2

    (asin t - bcos t) ^2 (b sint t + a cost t)^2 = a^2 + b^2

    I tried, believe me.
    Its too difficult.
    Last edited by mr fantastic; February 21st 2011 at 08:22 PM. Reason: Re-titled.
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  2. #2
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    Quote Originally Posted by ilyhyunbin View Post
    (asin t - bcos t)^2 + (b sint t + a cost t)^2 = a^2 + b^2

    I tried, believe me.
    Its too difficult.
    The red plus sign I added is not unimportant. Now expand and simplify using the Pythagorean Identity.
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  3. #3
    Forum Admin topsquark's Avatar
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    Maybe it's just because I'm up too late. What the heck are "b sint t" and "a cost t?"

    -Dan
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    Quote Originally Posted by topsquark View Post
    Maybe it's just because I'm up too late. What the heck are "b sint t" and "a cost t?"

    -Dan
    I believe that a and b are constants that are multiplying the sin(t) and cos(t) functions.
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  5. #5
    Forum Admin topsquark's Avatar
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    Well, the OP doesn't seem to have a problem with it (or hasn't come back yet.) My problem is that extra "t" in "sint t" and "cost t". Sorry for not being more clear.

    -Dan
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