The third one is wrong (the other two are fine). Your graph doesn't have a y intercept which implies x=0 is not valid when it is.
Compared to the first graph you move it 1 to the right and 'squeeze it by 4'.
It would be easiest to find where the graph crosses the axis and draw a curve to that effect.
It crosses the x-axis when 4(x-1)^2 = 0 and it crosses the y-axis when x=0:
It is no correct. For example must be a point of the graph .
Fernando Revilla
Edited: Sorry, I didnīt see the previous posts.
Have you seen e^(i*pi)'s attachment?
Fernando Revilla