start the problem by taking log on both sides.
So I have a question about this problem:
5e^2-x = 7e^x
i know you need to apply Ln to both sides, but first can you bring the 5 up to the exponent? or does this not apply...
meaning can you go
e^10-5x = e^7x
10-5x = 7x
10= 12x
x = 5/6?