f(x) = 3 - 3/3-2^(negative infinity) how do you solve this algebraically
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Originally Posted by FallenStar117 f(x) = 3 - 3/3-2^(negative infinity) how do you solve this algebraically Solve what? Do you have to simplify this? Is it some kind of limit? Numerically if what you have is the value is 0. (But even that expression has problems because does not have an actual value.) -Dan
You will get 0 over some number that gets infinitely smaller in the denominator, which will simplify to 0. It's not really a solution though. This seems, like topsquark suggested, to be some description of a limit problem.
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