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Math Help - Calculate:

  1. #1
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    Calculate:

    f(x) = 3 - 3/3-2^(negative infinity)

    how do you solve this algebraically
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  2. #2
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by FallenStar117 View Post
    f(x) = 3 - 3/3-2^(negative infinity)

    how do you solve this algebraically
    Solve what? Do you have to simplify this? Is it some kind of limit? Numerically if what you have is
    \displaystyle \frac{3 - 3}{3 - 2^{-\infty}}
    the value is 0. (But even that expression has problems because \displaystyle 2^{-\infty} does not have an actual value.)

    -Dan
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  3. #3
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    You will get 0 over some number that gets infinitely smaller in the denominator, which will simplify to 0.

    It's not really a solution though. This seems, like topsquark suggested, to be some description of a limit problem.
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