f(x) = 3 - 3/3-2^(negative infinity)
how do you solve this algebraically
Solve what? Do you have to simplify this? Is it some kind of limit? Numerically if what you have is
$\displaystyle \displaystyle \frac{3 - 3}{3 - 2^{-\infty}}$
the value is 0. (But even that expression has problems because $\displaystyle \displaystyle 2^{-\infty}$ does not have an actual value.)
-Dan