f(x) = log(base 4)(x-4) / 3 - 2log(base 4)x
I think whats throwing me off is the logs. I have no problem finding asymptotes for a rational function with simple variables. But this is confusing me.
Vertical asymptotes occur where the denominator is zero.
Therefore, there is a vertical asymptote at
I suggest that you re-write the function . . .
The denominator is: .
The function becomes: .
Using the Base-change Formula, we can convert to any base.
So we have: .