Given:
f(x) = log(base 4)(x-4) / 3 - 2log(base 4)x
I think whats throwing me off is the logs. I have no problem finding asymptotes for a rational function with simple variables. But this is confusing me.
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Given:
f(x) = log(base 4)(x-4) / 3 - 2log(base 4)x
I think whats throwing me off is the logs. I have no problem finding asymptotes for a rational function with simple variables. But this is confusing me.
Assuming
Sketch the graph using a table of values or technology for a better understanding.
Hello,
I am wondering how to solve for the horizontal asymptote
I found the vertical asymptote, but am stuck for the horizontal =(
Hello, FallenStar117!
Quote:
 \:=\: \dfrac{\log_4(x-4)}{3 - 2\log_4x})
Vertical asymptotes occur where the denominator is zero.
. .
Therefore, there is a vertical asymptote at
I suggest that you re-write the function . . .
The denominator is: .
The function becomes: .
Using the Base-change Formula, we can convert to any base.
So we have: .