If log4 N=p and log12 N=q, show that log3 48= I tried so many times but it seems to be so tough for me... can anyone help?
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This might be sending you the long way home but write out in terms of the logs given then change the base of all logs to base 3.
Originally Posted by MichaelLight If log4 N=p and log12 N=q, show that log3 48= I tried so many times but it seems to be so tough for me... can anyone help? How did "N" disappear? And where did "48" come from?
Originally Posted by pickslides This might be sending you the long way home but write out in terms of the logs given then change the base of all logs to base 3. I tried but i couldn't get the required answer, have you tried it before? Originally Posted by HallsofIvy How did "N" disappear? And where did "48" come from? I don't know...
try using for EDIT: forgot to mention you need as well. That is where "N" disappears.
Last edited by BAdhi; February 15th 2011 at 06:31 AM. Reason: latex edit
Hello, MichaelLight! My approach is worse that Pickslides' suggestion. I used the Base-Change formula. Divide numerator and denominator by . . Multiply by . . . .
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