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Math Help - Question 1

  1. #1
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    Post Question 1

    The values of x of 2(x+2)^2-8=0 are?
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  2. #2
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    Quote Originally Posted by zbest View Post
    The values of x of 2(x+2)^2-8=0 are?
    2(x+2)^2 - 8 = 0

    2(x+2)^2 = 8

    (x+2)^2 = 4

    x+2=\pm 2
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