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  1. #1
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    Post Question 1

    The values of x of 2(x+2)^2-8=0 are?
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  2. #2
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    Quote Originally Posted by zbest View Post
    The values of x of 2(x+2)^2-8=0 are?
    $\displaystyle 2(x+2)^2 - 8 = 0$

    $\displaystyle 2(x+2)^2 = 8$

    $\displaystyle (x+2)^2 = 4$

    $\displaystyle x+2=\pm 2$
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