find the solution set and draw the solution in the real number line.
|x+2| < |x (x - 1)|
all i can think is to transpose the right side of the in inequality like
|x+2| - |x (x - 1)|< 0 equate by zero
then i am stuck here... if i get the value of x by quadratic ... i don't kn0w to do this as a simple solving.